On Tue, 17 Dec 2024 11:54:32 +0800, Ma Ke make_ruc2021@163.com wrote:
When device_add(&dev->dev) failed, calling put_device() to explicitly release dev->dev. Otherwise, it could cause double free problem.
Who frees it doublely? If device_add() failed, the put_device is called inside device_add(), why we need to call it again?
Maybe you need to say more?
Thanks.
Found by code review.
Cc: stable@vger.kernel.org Fixes: 694a1116b405 ("virtio: Bind virtio device to device-tree node") Signed-off-by: Ma Ke make_ruc2021@163.com
drivers/virtio/virtio.c | 1 + 1 file changed, 1 insertion(+)
diff --git a/drivers/virtio/virtio.c b/drivers/virtio/virtio.c index b9095751e43b..ac721b5597e8 100644 --- a/drivers/virtio/virtio.c +++ b/drivers/virtio/virtio.c @@ -503,6 +503,7 @@ int register_virtio_device(struct virtio_device *dev)
out_of_node_put: of_node_put(dev->dev.of_node);
- put_device(&dev->dev);
out_ida_remove: ida_free(&virtio_index_ida, dev->index); out: -- 2.25.1