6.6-stable review patch. If anyone has any objections, please let me know.
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From: Wolfram Sang wsa+renesas@sang-engineering.com
[ Upstream commit 119736c7af442ab398dbb806865988c98ef60d46 ]
The to-be-fixed commit rightfully prevented that the registers will be cleared. However, the index must be cleared. Otherwise a read message will re-issue the last work. Fix it and add a comment describing the situation.
Fixes: c422b6a63024 ("i2c: testunit: don't erase registers after STOP") Signed-off-by: Wolfram Sang wsa+renesas@sang-engineering.com Reviewed-by: Andi Shyti andi.shyti@kernel.org Signed-off-by: Wolfram Sang wsa+renesas@sang-engineering.com Signed-off-by: Sasha Levin sashal@kernel.org --- drivers/i2c/i2c-slave-testunit.c | 7 +++++++ 1 file changed, 7 insertions(+)
diff --git a/drivers/i2c/i2c-slave-testunit.c b/drivers/i2c/i2c-slave-testunit.c index ca43e98cae1b2..23a11e4e92567 100644 --- a/drivers/i2c/i2c-slave-testunit.c +++ b/drivers/i2c/i2c-slave-testunit.c @@ -118,6 +118,13 @@ static int i2c_slave_testunit_slave_cb(struct i2c_client *client, queue_delayed_work(system_long_wq, &tu->worker, msecs_to_jiffies(10 * tu->regs[TU_REG_DELAY])); } + + /* + * Reset reg_idx to avoid that work gets queued again in case of + * STOP after a following read message. But do not clear TU regs + * here because we still need them in the workqueue! + */ + tu->reg_idx = 0; break;
case I2C_SLAVE_WRITE_REQUESTED: