On Wed, Mar 11, 2020 at 10:35:45AM -0700, Eric Biggers wrote:
On Wed, Mar 11, 2020 at 06:31:30AM +0000, Luis Chamberlain wrote:
On Tue, Mar 10, 2020 at 10:26:20PM -0700, Eric Biggers wrote:
On Wed, Mar 11, 2020 at 04:32:21AM +0000, Luis Chamberlain wrote:
On Tue, Mar 10, 2020 at 03:37:31PM -0700, Eric Biggers wrote:
From: Eric Biggers ebiggers@google.com
It's long been possible to disable kernel module autoloading completely by setting /proc/sys/kernel/modprobe to the empty string. This can be preferable
preferable but ... not documented. Or was this documented or recommended somewhere?
to setting it to a nonexistent file since it avoids the overhead of an attempted execve(), avoids potential deadlocks, and avoids the call to security_kernel_module_request() and thus on SELinux-based systems eliminates the need to write SELinux rules to dontaudit module_request.
Not that I know of, though I didn't look too hard. proc(5) mentions /proc/sys/kernel/modprobe but doesn't mention the empty string case.
In any case, it's been supported for a long time, and it's useful for the reasons I mentioned.
Sure. I think then its important to document it as such then, or perhaps make a kconfig option which sets this to empty and document it on the kconfig entry.
I'll send a man-pages patch to document it in proc(5).
Most users, including the one I have in mind, should just be able to run 'echo > /proc/sys/kernel/modprobe' early in the boot process. So I don't think the need for a kconfig option to control the default value has been clearly demonstrated yet. You're certainly welcome to send a patch for it if you believe it would be useful, though.
When doing a rewrite of some of this code I did wonder who would use this and clear it out. A kconfig entry would remove any doubt over its use and would allow one to skip the userspace / early init requirement to empty it out, therefore actually being safer because you are not racing against modules being loaded.
Is avoiding the race more suitable for your needs than echo'ing early on boot?
Luis