From: Michael Ellerman mpe@ellerman.id.au
[ Upstream commit 0464ed24380905d640030d368cd84a4e4d1e15e2 ]
Currently seq_buf_puts() will happily create a non null-terminated string for you in the buffer. This is particularly dangerous if the buffer is on the stack.
For example:
char buf[8]; char secret = "secret"; struct seq_buf s;
seq_buf_init(&s, buf, sizeof(buf)); seq_buf_puts(&s, "foo"); printk("Message is %s\n", buf);
Can result in:
Message is fooªªªªªsecret
We could require all users to memset() their buffer to zero before use. But that seems likely to be forgotten and lead to bugs.
Instead we can change seq_buf_puts() to always leave the buffer in a null-terminated state.
The only downside is that this makes the buffer 1 character smaller for seq_buf_puts(), but that seems like a good trade off.
Link: http://lkml.kernel.org/r/20181019042109.8064-1-mpe@ellerman.id.au
Acked-by: Kees Cook keescook@chromium.org Signed-off-by: Michael Ellerman mpe@ellerman.id.au Signed-off-by: Steven Rostedt (VMware) rostedt@goodmis.org Signed-off-by: Sasha Levin sashal@kernel.org --- lib/seq_buf.c | 6 +++++- 1 file changed, 5 insertions(+), 1 deletion(-)
diff --git a/lib/seq_buf.c b/lib/seq_buf.c index cb18469e1f49..5954f9fb6675 100644 --- a/lib/seq_buf.c +++ b/lib/seq_buf.c @@ -143,9 +143,13 @@ int seq_buf_puts(struct seq_buf *s, const char *str)
WARN_ON(s->size == 0);
+ /* Add 1 to len for the trailing null byte which must be there */ + len += 1; + if (seq_buf_can_fit(s, len)) { memcpy(s->buffer + s->len, str, len); - s->len += len; + /* Don't count the trailing null byte against the capacity */ + s->len += len - 1; return 0; } seq_buf_set_overflow(s);