On Thu, 23 Dec 2021, Alexander Lobakin wrote:
For now, that condition from remove_dot():
if (m && (s[n + m] == '.' || s[n + m] == 0))
which was designed to test if it's a dot or a \0 after the suffix is never satisfied. This is due to that s[n + m] always points to the last digit of a numeric suffix, not on the symbol next to it:
param_set_uint.0, s[n + m] is '0', s[n + m + 1] is '\0'
So it's off by one and was like that since 2014.
`-z uniq-symbol` linker flag which we are planning to use to
`-z unique-symbol`
Miroslav