11 May
2020
11 May
'20
8:28 p.m.
On Mon, 11 May 2020 14:59:20 +0000 David Laight David.Laight@ACULAB.COM wrote:
echo "Test command: $command" echo > error_log
- (! echo "$command" >> "$3" ) 2> /dev/null
- (! printf "%s" "$command" >> "$3" ) 2> /dev/null
WTF is the (! for ?? The (...) is a subshell. And ! inverts the exit status. Neither is needed at all.
This is done because the scripts are run with '-e' and will exit the script on any error.
This particular test is examining errors in the error log. The command being written into $3 is going to fail, and return an exit code. The "(! ..)" is needed, otherwise that failure will exit out the script.
-- Steve