Hi, First of all thanks for the review. More info and questions inline.
On Wed, Mar 17, 2021 at 07:00:56PM -0700, Kees Cook wrote:
On Sun, Mar 07, 2021 at 12:30:25PM +0100, John Wood wrote:
config LSM string "Ordered list of enabled LSMs"
- default "lockdown,yama,loadpin,safesetid,integrity,smack,selinux,tomoyo,apparmor,bpf" if DEFAULT_SECURITY_SMACK
- default "lockdown,yama,loadpin,safesetid,integrity,apparmor,selinux,smack,tomoyo,bpf" if DEFAULT_SECURITY_APPARMOR
- default "lockdown,yama,loadpin,safesetid,integrity,tomoyo,bpf" if DEFAULT_SECURITY_TOMOYO
- default "lockdown,yama,loadpin,safesetid,integrity,bpf" if DEFAULT_SECURITY_DAC
- default "lockdown,yama,loadpin,safesetid,integrity,selinux,smack,tomoyo,apparmor,bpf"
- default "brute,lockdown,yama,loadpin,safesetid,integrity,smack,selinux,tomoyo,apparmor,bpf" if DEFAULT_SECURITY_SMACK
- default "brute,lockdown,yama,loadpin,safesetid,integrity,apparmor,selinux,smack,tomoyo,bpf" if DEFAULT_SECURITY_APPARMOR
- default "brute,lockdown,yama,loadpin,safesetid,integrity,tomoyo,bpf" if DEFAULT_SECURITY_TOMOYO
- default "brute,lockdown,yama,loadpin,safesetid,integrity,bpf" if DEFAULT_SECURITY_DAC
- default "brute,lockdown,yama,loadpin,safesetid,integrity,selinux,smack,tomoyo,apparmor,bpf"
It probably doesn't matter much, but I think brute should be added between lockdown and yama.
What is the rationale for the stacking order (in relation with brute and lockdown)?
diff --git a/security/Makefile b/security/Makefile index 3baf435de541..1236864876da 100644 --- a/security/Makefile +++ b/security/Makefile @@ -36,3 +36,7 @@ obj-$(CONFIG_BPF_LSM) += bpf/ # Object integrity file lists subdir-$(CONFIG_INTEGRITY) += integrity obj-$(CONFIG_INTEGRITY) += integrity/
+# Object brute file lists +subdir-$(CONFIG_SECURITY_FORK_BRUTE) += brute +obj-$(CONFIG_SECURITY_FORK_BRUTE) += brute/
I don't think subdir is needed here? I think you can use obj-... like loadpin, etc.
loadpin also uses subdir just like selinux, smack, tomoyo, etc.. So, why is it not necessary for brute?
+#include <asm/current.h>
Why is this needed?
IIUC, the "current" macro is defined in this header. I try to include the appropiate header for every macro and function used.
+/**
- struct brute_stats - Fork brute force attack statistics.
- @lock: Lock to protect the brute_stats structure.
- @refc: Reference counter.
- @faults: Number of crashes.
- @jiffies: Last crash timestamp.
- @period: Crash period's moving average.
- This structure holds the statistical data shared by all the fork hierarchy
- processes.
- */
+struct brute_stats {
- spinlock_t lock;
- refcount_t refc;
- unsigned char faults;
- u64 jiffies;
- u64 period;
+};
I assume the max-255 "faults" will be explained... why is this so small?
If a brute force attack is running slowly for a long time, the application crash period's EMA is not suitable for the detection. This type of attack must be detected using a maximum number of faults. In this case, the BRUTE_MAX_FAULTS is defined as 200.
[...] +static struct brute_stats *brute_new_stats(void) +{
- struct brute_stats *stats;
- stats = kmalloc(sizeof(struct brute_stats), GFP_KERNEL);
- if (!stats)
return NULL;Since this is tied to process creation, I think it might make sense to have a dedicated kmem cache for this (instead of using the "generic" kmalloc). See kmem_cache_{create,*alloc,free}
Thanks, I will work on it for the next version.
- spin_lock_init(&stats->lock);
- refcount_set(&stats->refc, 1);
- stats->faults = 0;
- stats->jiffies = get_jiffies_64();
- stats->period = 0;
And either way, I'd recommend using the "z" variant of the allocator (kmem_cache_zalloc, kzalloc) to pre-zero everything (and then you can drop the "= 0" lines here).
Understood.
- return stats;
+}
+/**
- brute_share_stats() - Share the statistical data between processes.
- @src: Source of statistics to be shared.
- @dst: Destination of statistics to be shared.
- Copy the src's pointer to the statistical data structure to the dst's pointer
- to the same structure. Since there is a new process that shares the same
- data, increase the reference counter. The src's pointer cannot be NULL.
- It's mandatory to disable interrupts before acquiring the brute_stats::lock
- since the task_free hook can be called from an IRQ context during the
- execution of the task_alloc hook.
- */
+static void brute_share_stats(struct brute_stats *src,
struct brute_stats **dst)+{
- unsigned long flags;
- spin_lock_irqsave(&src->lock, flags);
- refcount_inc(&src->refc);
- *dst = src;
- spin_unlock_irqrestore(&src->lock, flags);
+}
+/**
- brute_task_alloc() - Target for the task_alloc hook.
- @task: Task being allocated.
- @clone_flags: Contains the flags indicating what should be shared.
- For a correct management of a fork brute force attack it is necessary that
- all the tasks hold statistical data. The same statistical data needs to be
- shared between all the tasks that hold the same memory contents or in other
- words, between all the tasks that have been forked without any execve call.
- To ensure this, if the current task doesn't have statistical data when forks,
- it is mandatory to allocate a new statistics structure and share it between
- this task and the new one being allocated. Otherwise, share the statistics
- that the current task already has.
- Return: -ENOMEM if the allocation of the new statistics structure fails. Zero
otherwise.- */
+static int brute_task_alloc(struct task_struct *task, unsigned long clone_flags) +{
- struct brute_stats **stats, **p_stats;
- stats = brute_stats_ptr(task);
- p_stats = brute_stats_ptr(current);
- if (likely(*p_stats)) {
brute_share_stats(*p_stats, stats);return 0;- }
- *stats = brute_new_stats();
- if (!*stats)
return -ENOMEM;- brute_share_stats(*stats, p_stats);
- return 0;
+}
During the task_alloc hook, aren't both "current" and "task" already immutable (in the sense that no lock needs to be held for brute_share_stats())?
I will work on it.
And what is the case where brute_stats_ptr(current) returns NULL?
Sorry, but I don't understand what you are trying to explain me. brute_stats_ptr(current) returns a pointer to a pointer. So, I think your question is: What's the purpose of the "if (likely(*p_stats))" check? If it is the case, this check is to guarantee that all the tasks have statistical data. If some task has been allocated prior the brute LSM initialization, this task doesn't have stats. So, with this check all the tasks that fork have stats.
+/**
- brute_task_execve() - Target for the bprm_committing_creds hook.
- @bprm: Points to the linux_binprm structure.
- When a forked task calls the execve system call, the memory contents are set
- with new values. So, in this scenario the parent's statistical data no need
- to be shared. Instead, a new statistical data structure must be allocated to
- start a new hierarchy. This condition is detected when the statistics
- reference counter holds a value greater than or equal to two (a fork always
- sets the statistics reference counter to a minimum of two since the parent
- and the child task are sharing the same data).
- However, if the execve function is called immediately after another execve
- call, althought the memory contents are reset, there is no need to allocate
- a new statistical data structure. This is possible because at this moment
- only one task (the task that calls the execve function) points to the data.
- In this case, the previous allocation is used but the statistics are reset.
- It's mandatory to disable interrupts before acquiring the brute_stats::lock
- since the task_free hook can be called from an IRQ context during the
- execution of the bprm_committing_creds hook.
- */
+static void brute_task_execve(struct linux_binprm *bprm) +{
- struct brute_stats **stats;
- unsigned long flags;
- stats = brute_stats_ptr(current);
- if (WARN(!*stats, "No statistical data\n"))
return;- spin_lock_irqsave(&(*stats)->lock, flags);
- if (!refcount_dec_not_one(&(*stats)->refc)) {
/* execve call after an execve call */(*stats)->faults = 0;(*stats)->jiffies = get_jiffies_64();(*stats)->period = 0;spin_unlock_irqrestore(&(*stats)->lock, flags);return;- }
- /* execve call after a fork call */
- spin_unlock_irqrestore(&(*stats)->lock, flags);
- *stats = brute_new_stats();
- WARN(!*stats, "Cannot allocate statistical data\n");
+}
I don't think any of this locking is needed -- you're always operating on "current", so its brute_stats will always be valid.
But another process (that share the same stats) could be modifying this concurrently.
Scenario 1: cpu 1 writes stats and cpu 2 writes stats. Scenario 2: cpu 1 writes stats, then IRQ on the same cpu writes stats.
I think it is possible. So AFAIK we need locking. Sorry if I am wrong.
+/**
- brute_task_free() - Target for the task_free hook.
- @task: Task about to be freed.
- The statistical data that is shared between all the fork hierarchy processes
- needs to be freed when this hierarchy disappears.
- It's mandatory to disable interrupts before acquiring the brute_stats::lock
- since the task_free hook can be called from an IRQ context during the
- execution of the task_free hook.
- */
+static void brute_task_free(struct task_struct *task) +{
- struct brute_stats **stats;
- unsigned long flags;
- bool refc_is_zero;
- stats = brute_stats_ptr(task);
- if (WARN(!*stats, "No statistical data\n"))
return;- spin_lock_irqsave(&(*stats)->lock, flags);
- refc_is_zero = refcount_dec_and_test(&(*stats)->refc);
- spin_unlock_irqrestore(&(*stats)->lock, flags);
- if (refc_is_zero) {
kfree(*stats);*stats = NULL;- }
+}
Same thing -- this is what dec_and_test is for: it's atomic, so no locking needed.
Ok, in this case I can see that the locking is not necessary due to the stats::refc is atomic. But in the previous case, faults, jiffies and period are not atomic. So I think the lock is necessary. If not, what am I missing?
Thanks, John Wood