On Mon, 2024-04-08 at 19:20 +0200, Benjamin Tissoires wrote:
[...]
That was my initial assumption too, but Alexei told me it was fine. And I think he is correct because kfree_rcu doesn't need the rcu_head to be initialized.
So in the end, we initialize the memory as a work_struct, and when that work kicks in, we reuse that exact same memory as the rcu_head. This is fine because that work will never be reused.
Oh, I get it, thank you for explanation.
Thanks, Eduard