On 3/19/25 23:18, Cong Wang wrote:
On Mon, Mar 17, 2025 at 10:52:25AM +0100, Michal Luczaj wrote:
Signal delivery during connect() may lead to a disconnect of an already established socket. That involves removing socket from any sockmap and resetting state to SS_UNCONNECTED. While it correctly restores socket's proto, a call to vsock_bpf_recvmsg() might have been already under way in another thread. If the connect()ing thread reassigns the vsock transport to NULL, the recvmsg()ing thread may trigger a WARN_ON_ONCE.
*THREAD 1* *THREAD 2*
connect / state = SS_CONNECTED / sock_map_update_elem vsock_bpf_recvmsg psock = sk_psock_get() lock sk if signal_pending unhash sock_map_remove_links
So vsock's ->recvmsg() should be restored after this, right? Then how is vsock_bpf_recvmsg() called afterward?
I'm not sure I understand the question, so I've added a header above: those are 2 parallel flows of execution. vsock_bpf_recvmsg() wasn't called afterwards. It was called before sock_map_remove_links(). Note that at the time of sock_map_remove_links() (in T1), vsock_bpf_recvmsg() is still executing (in T2).
state = SS_UNCONNECTEDrelease sk
connect transport = NULL lock sk WARN_ON_ONCE(!vsk->transport)
And I am wondering why we need to WARN here since we can handle this error case correctly?
The WARN and transport check are here for defensive measures, and to state a contract.
But I think I get your point. If we accept for a fact of life that BPF code should be able to handle transport disappearing - then WARN can be removed (while keeping the check) and this patch can be dropped.
My aim, instead, was to keep things consistent. By which I mean sticking to the conditions expressed in vsock_bpf_update_proto() as invariants; so that vsock with a psock is guaranteed to have transport assigned.