Re: segfault using __thread variable

Michael Hudson-Doyle michael.hudson@linaro.org writes:

I guess I don't understand the adrp code. My understanding is that:

0x00000000004b4b78 <+12>: adrp x0, 0x64c000

would result in 0x4b4000 + 0x64c000 in x0 and then

0x00000000004b4b7c <+16>: ldr x0, [x0,#776]

reads from 0x4b4000 + 0x64c000 + 776 but

(gdb) x 0x4b4000 + 0x64c000 + 776 0xb00308: Cannot access memory at address 0xb00308

(I'm not sure if the disassembly for adrp has the immediate shifted or not, but anyway:

Oh, I see the disassembly calculates the address...

(gdb) x/g 0x64c000 + 776 0x64c308: 0x0000000000648680 (gdb) p *((long long*)(0x64c000 + 776)) == ($x0 - $x1) $3 = true

So that bit makes sense now.

Cheers, mwh