Re: Query: What happens in case of char array overflow?

Viresh Kumar wrote:

When we have following declaration:

struct foo { char array[5]; .... };

And have a definition like:

struct foo foo_abc = { .array = "12345", };

Problem here is: size of array is 5 bytes and so we can actually add a string with four characters only to it, as '\0' will take an additional space.

But with my definition of foo_abc.. i had 5 characters + '\0'... that will make it 6 and that will overflow the array..

What will actually happen here?

• compiler will not add '\0' at all?
• or it will go outside of boundaries of array?

I think it will go outside of boundaries. You should avoid adding the \0 or redefine char array to hold up to 6 chars.

Regards